[n+(1-n)]-[2n+(2-n)]=

Solution for [n+(1-n)]-[2n+(2-n)]= equation:

Simplifying
[n + (1 + -1n)] + -1[2n + (2 + -1n)] = 0

Remove parenthesis around (1 + -1n)
[n + 1 + -1n] + -1[2n + (2 + -1n)] = 0

Reorder the terms:
[1 + n + -1n] + -1[2n + (2 + -1n)] = 0

Combine like terms: n + -1n = 0
[1 + 0] + -1[2n + (2 + -1n)] = 0
[1] + -1[2n + (2 + -1n)] = 0
1 + -1[2n + (2 + -1n)] = 0

Remove parenthesis around (2 + -1n)
1 + -1[2n + 2 + -1n] = 0

Reorder the terms:
1 + -1[2 + 2n + -1n] = 0

Combine like terms: 2n + -1n = 1n
1 + -1[2 + 1n] = 0
1 + [2 * -1 + 1n * -1] = 0
1 + [-2 + -1n] = 0

Combine like terms: 1 + -2 = -1
-1 + -1n = 0

Solving
-1 + -1n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1n = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1n = 0 + 1
-1n = 0 + 1

Combine like terms: 0 + 1 = 1
-1n = 1

Divide each side by '-1'.
n = -1

Simplifying
n = -1